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1000404103131 = 32313839362083
BaseRepresentation
bin11101000111011001011…
…10110010111111011011
310112122012212210222202200
432203230232302333123
5112342311422300011
62043325043501243
7132163642400166
oct16435456627733
93478185728680
101000404103131
113562a6043624
12141a75387823
1373450c15914
14365c3d98add
151b051e8a856
hexe8ecbb2fdb

1000404103131 has 24 divisors (see below), whose sum is σ = 1495536746496. Its totient is φ = 643736758320.

The previous prime is 1000404103063. The next prime is 1000404103151. The reversal of 1000404103131 is 1313014040001.

It is not a de Polignac number, because 1000404103131 - 211 = 1000404101083 is a prime.

It is a super-2 number, since 2×10004041031312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1000404103151) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4574185 + ... + 4787898.

It is an arithmetic number, because the mean of its divisors is an integer number (62314031104).

Almost surely, 21000404103131 is an apocalyptic number.

1000404103131 is a deficient number, since it is larger than the sum of its proper divisors (495132643365).

1000404103131 is a wasteful number, since it uses less digits than its factorization.

1000404103131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9362503 (or 9362500 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1000404103131 its reverse (1313014040001), we get a palindrome (2313418143132).

The spelling of 1000404103131 in words is "one trillion, four hundred four million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 3 9 31 93 279 383 1149 3447 11873 35619 106857 9362083 28086249 84258747 290224573 870673719 2612021157 3585677789 10757033367 32271100101 111156011459 333468034377 1000404103131