100040473 has 4 divisors (see below), whose sum is σ = 107735908. Its totient is φ = 92345040.

The previous prime is 100040471. The next prime is 100040477. The reversal of 100040473 is 374040001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 374040001 = 17 ⋅22002353.

It can be written as a sum of positive squares in 2 ways, for example, as 18896409 + 81144064 = 4347^2 + 9008^2 .

It is a cyclic number.

It is not a de Polignac number, because 100040473 - 2¹ = 100040471 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100040473.

It is not an unprimeable number, because it can be changed into a prime (100040471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3847698 + ... + 3847723.

It is an arithmetic number, because the mean of its divisors is an integer number (26933977).

Almost surely, 2^100040473 is an apocalyptic number.

100040473 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

100040473 is a deficient number, since it is larger than the sum of its proper divisors (7695435).

100040473 is an equidigital number, since it uses as much as digits as its factorization.

100040473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7695434.

The product of its (nonzero) digits is 336, while the sum is 19.

The square root of 100040473 is about 10002.0234452835. The cubic root of 100040473 is about 464.2214945901.

Adding to 100040473 its reverse (374040001), we get a palindrome (474080474).

The spelling of 100040473 in words is "one hundred million, forty thousand, four hundred seventy-three".