Base | Representation |
---|---|
bin | 101110100101011100… |
… | …0011110001001011111 |
3 | 100120012222222021102211 |
4 | 1131022320132021133 |
5 | 3114340341042333 |
6 | 113542532301251 |
7 | 10141045526545 |
oct | 1351270361137 |
9 | 316188867384 |
10 | 100040565343 |
11 | 39477322484 |
12 | 1747b471827 |
13 | 95840436c4 |
14 | 4bb05bdd95 |
15 | 2907a9decd |
hex | 174ae1e25f |
100040565343 has 4 divisors (see below), whose sum is σ = 103490240040. Its totient is φ = 96590890648.
The previous prime is 100040565311. The next prime is 100040565419. The reversal of 100040565343 is 343565040001.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 343565040001 = 751 ⋅457476751.
It is a cyclic number.
It is not a de Polignac number, because 100040565343 - 25 = 100040565311 is a prime.
It is a super-2 number, since 2×1000405653432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100040560343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1724837305 + ... + 1724837362.
It is an arithmetic number, because the mean of its divisors is an integer number (25872560010).
Almost surely, 2100040565343 is an apocalyptic number.
100040565343 is a deficient number, since it is larger than the sum of its proper divisors (3449674697).
100040565343 is an equidigital number, since it uses as much as digits as its factorization.
100040565343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3449674696.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 100040565343 in words is "one hundred billion, forty million, five hundred sixty-five thousand, three hundred forty-three".
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