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100041020544005 = 559503674199013
BaseRepresentation
bin10110101111110010011101…
…011111100001010000000101
3111010012211100201201001222022
4112233302131133201100011
5101103033002224402010
6552434113235212525
730033503515050062
oct2657623537412005
9433184321631868
10100041020544005
1129970182040012
12b278753447145
1343a8a9b7795a8
141a9c022b57c69
15b8746ab94d55
hex5afc9d7e1405

100041020544005 has 16 divisors (see below), whose sum is σ = 122326669100160. Its totient is φ = 78519913733568.

The previous prime is 100041020543963. The next prime is 100041020544071. The reversal of 100041020544005 is 500445020140001.

It is a cyclic number.

It is not a de Polignac number, because 100041020544005 - 28 = 100041020543749 is a prime.

It is a super-2 number, since 2×1000410205440052 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 336951122 + ... + 337247891.

It is an arithmetic number, because the mean of its divisors is an integer number (7645416818760).

Almost surely, 2100041020544005 is an apocalyptic number.

It is an amenable number.

100041020544005 is a deficient number, since it is larger than the sum of its proper divisors (22285648556155).

100041020544005 is an equidigital number, since it uses as much as digits as its factorization.

100041020544005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 674199580.

The product of its (nonzero) digits is 3200, while the sum is 26.

Adding to 100041020544005 its reverse (500445020140001), we get a palindrome (600486040684006).

The spelling of 100041020544005 in words is "one hundred trillion, forty-one billion, twenty million, five hundred forty-four thousand, five".

Divisors: 1 5 59 295 503 2515 29677 148385 674199013 3370995065 39777741767 198888708835 339122103539 1695610517695 20008204108801 100041020544005