1000411041401 has 4 divisors (see below), whose sum is σ = 1000435808400. Its totient is φ = 1000386274404.

The previous prime is 1000411041367. The next prime is 1000411041439. The reversal of 1000411041401 is 1041401140001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000411041401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1000411041401.

It is not an unprimeable number, because it can be changed into a prime (1000411041481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12322811 + ... + 12403728.

It is an arithmetic number, because the mean of its divisors is an integer number (250108952100).

Almost surely, 2^{1000411041401} is an apocalyptic number.

It is an amenable number.

1000411041401 is a deficient number, since it is larger than the sum of its proper divisors (24766999).

1000411041401 is an equidigital number, since it uses as much as digits as its factorization.

1000411041401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24766998.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 1000411041401 its reverse (1041401140001), we get a palindrome (2041812181402).

The spelling of 1000411041401 in words is "one trillion, four hundred eleven million, forty-one thousand, four hundred one".