10004120023 has 4 divisors (see below), whose sum is σ = 10005200128. Its totient is φ = 10003039920.

The previous prime is 10004120017. The next prime is 10004120039. The reversal of 10004120023 is 32002140001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10004120023 - 2⁹ = 10004119511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10004119985 and 10004120012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10004120003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 526038 + ... + 544723.

It is an arithmetic number, because the mean of its divisors is an integer number (2501300032).

Almost surely, 2^10004120023 is an apocalyptic number.

10004120023 is a deficient number, since it is larger than the sum of its proper divisors (1080105).

10004120023 is an equidigital number, since it uses as much as digits as its factorization.

10004120023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1080104.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 10004120023 its reverse (32002140001), we get a palindrome (42006260024).

The spelling of 10004120023 in words is "ten billion, four million, one hundred twenty thousand, twenty-three".