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1000414012114 = 21145473364187
BaseRepresentation
bin11101000111011010101…
…00100110001011010010
310112122020120110102100001
432203231110212023102
5112342321441341424
62043330040120214
7132164122540306
oct16435524461322
93478216412301
101000414012114
113563006a1370
12141a7876606a
1373452ca4c1a
14365c5417d06
151b052c96844
hexe8ed5262d2

1000414012114 has 8 divisors (see below), whose sum is σ = 1637041110768. Its totient is φ = 454733641860.

The previous prime is 1000414012067. The next prime is 1000414012133. The reversal of 1000414012114 is 4112104140001.

1000414012114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1000414012091 and 1000414012100.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22736682072 + ... + 22736682115.

It is an arithmetic number, because the mean of its divisors is an integer number (204630138846).

Almost surely, 21000414012114 is an apocalyptic number.

1000414012114 is a deficient number, since it is larger than the sum of its proper divisors (636627098654).

1000414012114 is a wasteful number, since it uses less digits than its factorization.

1000414012114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45473364200.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 1000414012114 its reverse (4112104140001), we get a palindrome (5112518152115).

The spelling of 1000414012114 in words is "one trillion, four hundred fourteen million, twelve thousand, one hundred fourteen".

Divisors: 1 2 11 22 45473364187 90946728374 500207006057 1000414012114