10004202111133 has 4 divisors (see below), whose sum is σ = 10004208757888. Its totient is φ = 10004195464380.

The previous prime is 10004202111109. The next prime is 10004202111143. The reversal of 10004202111133 is 33111120240001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 10004202111133 - 2²¹ = 10004200013981 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10004202111133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10004202111103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131518 + ... + 4475008.

It is an arithmetic number, because the mean of its divisors is an integer number (2501052189472).

Almost surely, 2^{10004202111133} is an apocalyptic number.

It is an amenable number.

10004202111133 is a deficient number, since it is larger than the sum of its proper divisors (6646755).

10004202111133 is an equidigital number, since it uses as much as digits as its factorization.

10004202111133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6646754.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10004202111133 its reverse (33111120240001), we get a palindrome (43115322351134).

The spelling of 10004202111133 in words is "ten trillion, four billion, two hundred two million, one hundred eleven thousand, one hundred thirty-three".