Base | Representation |
---|---|
bin | 10010101000100110… |
… | …11001000110110111 |
3 | 221211012212022112022 |
4 | 21110103121012313 |
5 | 130442100214221 |
6 | 4332414543355 |
7 | 502626116651 |
oct | 112423310667 |
9 | 27735768468 |
10 | 10004304311 |
11 | 42741949a1 |
12 | 1b32507b5b |
13 | c358666c1 |
14 | 6ac9636d1 |
15 | 3d845d4ab |
hex | 2544d91b7 |
10004304311 has 4 divisors (see below), whose sum is σ = 10274690952. Its totient is φ = 9733917672.
The previous prime is 10004304301. The next prime is 10004304341. The reversal of 10004304311 is 11340340001.
10004304311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11340340001 = 547 ⋅20731883.
It is not a de Polignac number, because 10004304311 - 222 = 10000110007 is a prime.
It is a super-2 number, since 2×100043043112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10004304311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10004304301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135193265 + ... + 135193338.
It is an arithmetic number, because the mean of its divisors is an integer number (2568672738).
Almost surely, 210004304311 is an apocalyptic number.
10004304311 is a deficient number, since it is larger than the sum of its proper divisors (270386641).
10004304311 is an equidigital number, since it uses as much as digits as its factorization.
10004304311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 270386640.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 10004304311 its reverse (11340340001), we get a palindrome (21344644312).
The spelling of 10004304311 in words is "ten billion, four million, three hundred four thousand, three hundred eleven".
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