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100044341131 = 7171018323849
BaseRepresentation
bin101110100101100011…
…0110111111110001011
3100120020021002002211211
41131023012313332023
53114342322404011
6113543145233551
710141122603640
oct1351306677613
9316207062754
10100044341131
1139479471269
12174807928b7
139584a661b7
144bb0cc3dc7
152908097b21
hex174b1b7f8b

100044341131 has 16 divisors (see below), whose sum is σ = 122260708800. Its totient is φ = 79908940800.

The previous prime is 100044341123. The next prime is 100044341161. The reversal of 100044341131 is 131143440001.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 100044341131 - 23 = 100044341123 is a prime.

It is a super-2 number, since 2×1000443411312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (100044341161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4149906 + ... + 4173943.

It is an arithmetic number, because the mean of its divisors is an integer number (7641294300).

Almost surely, 2100044341131 is an apocalyptic number.

100044341131 is a deficient number, since it is larger than the sum of its proper divisors (22216367669).

100044341131 is a wasteful number, since it uses less digits than its factorization.

100044341131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8323974.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 100044341131 its reverse (131143440001), we get a palindrome (231187781132).

The spelling of 100044341131 in words is "one hundred billion, forty-four million, three hundred forty-one thousand, one hundred thirty-one".

Divisors: 1 7 17 101 119 707 1717 12019 8323849 58266943 141505433 840708749 990538031 5884961243 14292048733 100044341131