Search a number
-
+
100049053 = 1333123251
BaseRepresentation
bin1011111011010…
…10000010011101
320222021000111111
411331222002131
5201103032203
613532222021
72323255126
oct575520235
9228230444
10100049053
1151525375
122960a911
131795cc30
14d40504d
158bb426d
hex5f6a09d

100049053 has 8 divisors (see below), whose sum is σ = 108075296. Its totient is φ = 92070000.

The previous prime is 100049051. The next prime is 100049093. The reversal of 100049053 is 350940001.

100049053 is nontrivially palindromic in base 14.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100049053 - 21 = 100049051 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100049051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7323 + ... + 15928.

It is an arithmetic number, because the mean of its divisors is an integer number (13509412).

Almost surely, 2100049053 is an apocalyptic number.

100049053 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

100049053 is a deficient number, since it is larger than the sum of its proper divisors (8026243).

100049053 is a wasteful number, since it uses less digits than its factorization.

100049053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23595.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 100049053 is about 10002.4523492991. The cubic root of 100049053 is about 464.2347655741.

Adding to 100049053 its reverse (350940001), we get a palindrome (450989054).

The spelling of 100049053 in words is "one hundred million, forty-nine thousand, fifty-three".

Divisors: 1 13 331 4303 23251 302263 7696081 100049053