Base | Representation |
---|---|
bin | 101110100101111000… |
… | …0011010111101011001 |
3 | 100120021000120102210010 |
4 | 1131023300122331121 |
5 | 3114403114413340 |
6 | 113544214512133 |
7 | 10141314304515 |
oct | 1351360327531 |
9 | 316230512703 |
10 | 100055232345 |
11 | 3948462aa72 |
12 | 17484365649 |
13 | 95870aa5c3 |
14 | 4bb251b145 |
15 | 2908ee9b80 |
hex | 174bc1af59 |
100055232345 has 8 divisors (see below), whose sum is σ = 160088371776. Its totient is φ = 53362790576.
The previous prime is 100055232307. The next prime is 100055232373. The reversal of 100055232345 is 543232550001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100055232345 - 27 = 100055232217 is a prime.
It is a super-2 number, since 2×1000552323452 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3335174397 + ... + 3335174426.
It is an arithmetic number, because the mean of its divisors is an integer number (20011046472).
Almost surely, 2100055232345 is an apocalyptic number.
100055232345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
100055232345 is a deficient number, since it is larger than the sum of its proper divisors (60033139431).
100055232345 is an equidigital number, since it uses as much as digits as its factorization.
100055232345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6670348831.
The product of its (nonzero) digits is 18000, while the sum is 30.
Adding to 100055232345 its reverse (543232550001), we get a palindrome (643287782346).
The spelling of 100055232345 in words is "one hundred billion, fifty-five million, two hundred thirty-two thousand, three hundred forty-five".
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