10006485125143 has 8 divisors (see below), whose sum is σ = 10875079107200. Its totient is φ = 9152014622688.

The previous prime is 10006485125129. The next prime is 10006485125159. The reversal of 10006485125143 is 34152158460001.

10006485125143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10006485125143 - 2¹⁷ = 10006484994071 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10006485125096 and 10006485125105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10006485125113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3530868423 + ... + 3530871256.

It is an arithmetic number, because the mean of its divisors is an integer number (1359384888400).

Almost surely, 2^{10006485125143} is an apocalyptic number.

10006485125143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

10006485125143 is a deficient number, since it is larger than the sum of its proper divisors (868593982057).

10006485125143 is a wasteful number, since it uses less digits than its factorization.

10006485125143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7061739801.

The product of its (nonzero) digits is 115200, while the sum is 40.

The spelling of 10006485125143 in words is "ten trillion, six billion, four hundred eighty-five million, one hundred twenty-five thousand, one hundred forty-three".