1000749054703 has 4 divisors (see below), whose sum is σ = 1004285270728. Its totient is φ = 997212838680.

The previous prime is 1000749054673. The next prime is 1000749054709. The reversal of 1000749054703 is 3074509470001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1000749054703 - 2⁵ = 1000749054671 is a prime.

It is a super-3 number, since 3×1000749054703³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000749054709) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1768107588 + ... + 1768108153.

It is an arithmetic number, because the mean of its divisors is an integer number (251071317682).

Almost surely, 2^{1000749054703} is an apocalyptic number.

1000749054703 is a deficient number, since it is larger than the sum of its proper divisors (3536216025).

1000749054703 is an equidigital number, since it uses as much as digits as its factorization.

1000749054703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3536216024.

The product of its (nonzero) digits is 105840, while the sum is 40.

The spelling of 1000749054703 in words is "one trillion, seven hundred forty-nine million, fifty-four thousand, seven hundred three".