100101111020113 has 48 divisors (see below), whose sum is σ = 121293057844224. Its totient is φ = 82278742533120.

The previous prime is 100101111020089. The next prime is 100101111020117. The reversal of 100101111020113 is 311020111101001.

It is not a de Polignac number, because 100101111020113 - 2²⁵ = 100101077465681 is a prime.

It is a super-3 number, since 3×100101111020113³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100101111020093 and 100101111020102.

It is not an unprimeable number, because it can be changed into a prime (100101111020117) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 742649181 + ... + 742783957.

It is an arithmetic number, because the mean of its divisors is an integer number (2526938705088).

Almost surely, 2^{100101111020113} is an apocalyptic number.

It is an amenable number.

100101111020113 is a deficient number, since it is larger than the sum of its proper divisors (21191946824111).

100101111020113 is a wasteful number, since it uses less digits than its factorization.

100101111020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139262 (or 139255 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 100101111020113 its reverse (311020111101001), we get a palindrome (411121222121114).

The spelling of 100101111020113 in words is "one hundred trillion, one hundred one billion, one hundred eleven million, twenty thousand, one hundred thirteen".