1001012100113 has 4 divisors (see below), whose sum is σ = 1001104531968. Its totient is φ = 1000919668260.

The previous prime is 1001012100107. The next prime is 1001012100149. The reversal of 1001012100113 is 3110012101001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1001012100113 - 2¹⁶ = 1001012034577 is a prime.

It is a super-2 number, since 2×1001012100113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1001012100094 and 1001012100103.

It is not an unprimeable number, because it can be changed into a prime (1001012100103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46199681 + ... + 46221342.

It is an arithmetic number, because the mean of its divisors is an integer number (250276132992).

Almost surely, 2^{1001012100113} is an apocalyptic number.

It is an amenable number.

1001012100113 is a deficient number, since it is larger than the sum of its proper divisors (92431855).

1001012100113 is an equidigital number, since it uses as much as digits as its factorization.

1001012100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92431854.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 1001012100113 its reverse (3110012101001), we get a palindrome (4111024201114).

The spelling of 1001012100113 in words is "one trillion, one billion, twelve million, one hundred thousand, one hundred thirteen".