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100102030130031 = 333367343376677
BaseRepresentation
bin10110110000101011010001…
…111100100111101101101111
3111010102122211121000011101120
4112300223101330213231233
5101110032424203130111
6552522123210312023
730041063424012216
oct2660532174475557
9433378747004346
10100102030130031
112999403a398a96
12b28853b428613
1343b177241bc57
141aa0d6d73207d
15b88d3bd6e406
hex5b0ad1f27b6f

100102030130031 has 4 divisors (see below), whose sum is σ = 133469373506712. Its totient is φ = 66734686753352.

The previous prime is 100102030130017. The next prime is 100102030130051. The reversal of 100102030130031 is 130031030201001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100102030130031 - 221 = 100102028032879 is a prime.

It is a super-2 number, since 2×1001020301300312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100102030130051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16683671688336 + ... + 16683671688341.

It is an arithmetic number, because the mean of its divisors is an integer number (33367343376678).

Almost surely, 2100102030130031 is an apocalyptic number.

100102030130031 is a deficient number, since it is larger than the sum of its proper divisors (33367343376681).

100102030130031 is an equidigital number, since it uses as much as digits as its factorization.

100102030130031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33367343376680.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 100102030130031 its reverse (130031030201001), we get a palindrome (230133060331032).

The spelling of 100102030130031 in words is "one hundred trillion, one hundred two billion, thirty million, one hundred thirty thousand, thirty-one".

Divisors: 1 3 33367343376677 100102030130031