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100102131411 = 333367377137
BaseRepresentation
bin101110100111010001…
…1010100111011010011
3100120101021211011012120
41131032203110323103
53120002121201121
6113553012025323
710142424035502
oct1351643247323
9316337734176
10100102131411
11394a9052a27
1217498002243
139593a1b429
144bb8848839
15290d1b0bc6
hex174e8d4ed3

100102131411 has 4 divisors (see below), whose sum is σ = 133469508552. Its totient is φ = 66734754272.

The previous prime is 100102131397. The next prime is 100102131431. The reversal of 100102131411 is 114131201001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100102131411 - 211 = 100102129363 is a prime.

It is a super-2 number, since 2×1001021314112 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (100102131431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16683688566 + ... + 16683688571.

It is an arithmetic number, because the mean of its divisors is an integer number (33367377138).

Almost surely, 2100102131411 is an apocalyptic number.

100102131411 is a deficient number, since it is larger than the sum of its proper divisors (33367377141).

100102131411 is an equidigital number, since it uses as much as digits as its factorization.

100102131411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33367377140.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 100102131411 its reverse (114131201001), we get a palindrome (214233332412).

The spelling of 100102131411 in words is "one hundred billion, one hundred two million, one hundred thirty-one thousand, four hundred eleven".

Divisors: 1 3 33367377137 100102131411