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10010513403535 = 514913436930743
BaseRepresentation
bin1001000110101100000100…
…0110000110111010001111
31022102222212220001111012111
42101223001012012322033
52303003012412403120
633142433311444451
72052143565656461
oct221530106067217
938388786044174
1010010513403535
11320a48692a777
121158130826727
13577cab311868
14268723536131
151255e2e1575a
hex91ac1186e8f

10010513403535 has 8 divisors (see below), whose sum is σ = 12093237669600. Its totient is φ = 7954662999264.

The previous prime is 10010513403529. The next prime is 10010513403551. The reversal of 10010513403535 is 53530431501001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10010513403535 - 219 = 10010512879247 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10010513403497 and 10010513403506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6718464627 + ... + 6718466116.

It is an arithmetic number, because the mean of its divisors is an integer number (1511654708700).

Almost surely, 210010513403535 is an apocalyptic number.

10010513403535 is a deficient number, since it is larger than the sum of its proper divisors (2082724266065).

10010513403535 is a wasteful number, since it uses less digits than its factorization.

10010513403535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13436930897.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 10010513403535 its reverse (53530431501001), we get a palindrome (63540944904536).

The spelling of 10010513403535 in words is "ten trillion, ten billion, five hundred thirteen million, four hundred three thousand, five hundred thirty-five".

Divisors: 1 5 149 745 13436930743 67184653715 2002102680707 10010513403535