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10010925481 = 31132189471
BaseRepresentation
bin10010101001011001…
…01001100110101001
3221211200022201001211
421110230221212221
5131000244103411
64333212513121
7503036314444
oct112454514651
927750281054
1010010925481
1142779a7537
121b3477b7a1
13c3704435b
146ad7a865b
153d8d1a221
hex254b299a9

10010925481 has 4 divisors (see below), whose sum is σ = 10043115264. Its totient is φ = 9978735700.

The previous prime is 10010925479. The next prime is 10010925569. The reversal of 10010925481 is 18452901001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10010925481 - 21 = 10010925479 is a prime.

It is a super-2 number, since 2×100109254812 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10010925451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16094425 + ... + 16095046.

It is an arithmetic number, because the mean of its divisors is an integer number (2510778816).

Almost surely, 210010925481 is an apocalyptic number.

It is an amenable number.

10010925481 is a deficient number, since it is larger than the sum of its proper divisors (32189783).

10010925481 is an equidigital number, since it uses as much as digits as its factorization.

10010925481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32189782.

The product of its (nonzero) digits is 2880, while the sum is 31.

The spelling of 10010925481 in words is "ten billion, ten million, nine hundred twenty-five thousand, four hundred eighty-one".

Divisors: 1 311 32189471 10010925481