1001101300211 has 4 divisors (see below), whose sum is σ = 1001118887592. Its totient is φ = 1001083712832.

The previous prime is 1001101300159. The next prime is 1001101300319. The reversal of 1001101300211 is 1120031011001.

It is a happy number.

1001101300211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001101300211 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1001101300192 and 1001101300201.

It is not an unprimeable number, because it can be changed into a prime (1001101306211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8708030 + ... + 8822243.

It is an arithmetic number, because the mean of its divisors is an integer number (250279721898).

Almost surely, 2^{1001101300211} is an apocalyptic number.

1001101300211 is a deficient number, since it is larger than the sum of its proper divisors (17587381).

1001101300211 is an equidigital number, since it uses as much as digits as its factorization.

1001101300211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17587380.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 1001101300211 its reverse (1120031011001), we get a palindrome (2121132311212).

The spelling of 1001101300211 in words is "one trillion, one billion, one hundred one million, three hundred thousand, two hundred eleven".