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10011022021113 = 322365632280079
BaseRepresentation
bin1001000110101101111101…
…1010010101000111111001
31022110001012100002221100120
42101223133122111013321
52303010033114133423
633143000001123453
72052162313104531
oct221533732250771
938401170087316
1010011022021113
11320a717a42683
121158253029589
1357805c7c31c9
14268770cd24c1
151256228d1ee3
hex91adf6951f9

10011022021113 has 16 divisors (see below), whose sum is σ = 13409934827520. Its totient is φ = 6643071095184.

The previous prime is 10011022021061. The next prime is 10011022021139. The reversal of 10011022021113 is 31112022011001.

It is not a de Polignac number, because 10011022021113 - 210 = 10011022020089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10011022021092 and 10011022021101.

It is not an unprimeable number, because it can be changed into a prime (10011022021163) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3250608 + ... + 5530686.

It is an arithmetic number, because the mean of its divisors is an integer number (838120926720).

Almost surely, 210011022021113 is an apocalyptic number.

It is an amenable number.

10011022021113 is a deficient number, since it is larger than the sum of its proper divisors (3398912806407).

10011022021113 is a wasteful number, since it uses less digits than its factorization.

10011022021113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2286868.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 10011022021113 its reverse (31112022011001), we get a palindrome (41123044032114).

The spelling of 10011022021113 in words is "ten trillion, eleven billion, twenty-two million, twenty-one thousand, one hundred thirteen".

Divisors: 1 3 223 669 6563 19689 1463549 2280079 4390647 6840237 508457617 1525372851 14964158477 44892475431 3337007340371 10011022021113