Base | Representation |
---|---|
bin | 101110100111100100… |
… | …1010111001011100001 |
3 | 100120101222120201102211 |
4 | 1131033021113023201 |
5 | 3120012144231423 |
6 | 113554005442121 |
7 | 10142604553552 |
oct | 1351711271341 |
9 | 316358521384 |
10 | 100112102113 |
11 | 39503743081 |
12 | 1749b410341 |
13 | 9595acc85a |
14 | 4bb9cc2329 |
15 | 290ded010d |
hex | 174f2572e1 |
100112102113 has 8 divisors (see below), whose sum is σ = 100479263616. Its totient is φ = 99745035600.
The previous prime is 100112102081. The next prime is 100112102221. The reversal of 100112102113 is 311201211001.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100112102113 - 25 = 100112102081 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100112102093 and 100112102102.
It is not an unprimeable number, because it can be changed into a prime (100112102413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2624568 + ... + 2662438.
It is an arithmetic number, because the mean of its divisors is an integer number (12559907952).
Almost surely, 2100112102113 is an apocalyptic number.
It is an amenable number.
100112102113 is a deficient number, since it is larger than the sum of its proper divisors (367161503).
100112102113 is an equidigital number, since it uses as much as digits as its factorization.
100112102113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47495.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 100112102113 its reverse (311201211001), we get a palindrome (411313313114).
The spelling of 100112102113 in words is "one hundred billion, one hundred twelve million, one hundred two thousand, one hundred thirteen".
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