Base | Representation |
---|---|
bin | 10110110000110100101011… |
… | …111100100100110001011111 |
3 | 111010110121220110200211010022 |
4 | 112300310223330210301133 |
5 | 101110214120240031030 |
6 | 552530513321502355 |
7 | 30041601623344145 |
oct | 2660645374446137 |
9 | 433417813624108 |
10 | 100112130002015 |
11 | 2999835251732a |
12 | b28a4999419bb |
13 | 43b26c1a06871 |
14 | 1aa164ac51595 |
15 | b8922d8a8de5 |
hex | 5b0d2bf24c5f |
100112130002015 has 4 divisors (see below), whose sum is σ = 120134556002424. Its totient is φ = 80089704001608.
The previous prime is 100112130001973. The next prime is 100112130002023. The reversal of 100112130002015 is 510200031211001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100112130002015 - 222 = 100112125807711 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100112130001984 and 100112130002002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10011213000197 + ... + 10011213000206.
It is an arithmetic number, because the mean of its divisors is an integer number (30033639000606).
Almost surely, 2100112130002015 is an apocalyptic number.
100112130002015 is a deficient number, since it is larger than the sum of its proper divisors (20022426000409).
100112130002015 is an equidigital number, since it uses as much as digits as its factorization.
100112130002015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20022426000408.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 100112130002015 its reverse (510200031211001), we get a palindrome (610312161213016).
The spelling of 100112130002015 in words is "one hundred trillion, one hundred twelve billion, one hundred thirty million, two thousand, fifteen".
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