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100112130301 = 819112222211
BaseRepresentation
bin101110100111100100…
…1011110000011111101
3100120101222122011002211
41131033021132003331
53120012201132201
6113554010220421
710142605032001
oct1351711360375
9316358564084
10100112130301
1139503762277
121749b424711
139595b0c631
144bb9ccc701
15290ded8651
hex174f25e0fd

100112130301 has 4 divisors (see below), whose sum is σ = 100124360704. Its totient is φ = 100099899900.

The previous prime is 100112130281. The next prime is 100112130319. The reversal of 100112130301 is 103031211001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100112130301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100112130901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6102915 + ... + 6119296.

It is an arithmetic number, because the mean of its divisors is an integer number (25031090176).

Almost surely, 2100112130301 is an apocalyptic number.

It is an amenable number.

100112130301 is a deficient number, since it is larger than the sum of its proper divisors (12230403).

100112130301 is an equidigital number, since it uses as much as digits as its factorization.

100112130301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12230402.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100112130301 its reverse (103031211001), we get a palindrome (203143341302).

The spelling of 100112130301 in words is "one hundred billion, one hundred twelve million, one hundred thirty thousand, three hundred one".

Divisors: 1 8191 12222211 100112130301