100113000113 has 4 divisors (see below), whose sum is σ = 114414857280. Its totient is φ = 85811142948.

The previous prime is 100113000067. The next prime is 100113000137. The reversal of 100113000113 is 311000311001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100113000113 - 2¹⁸ = 100112737969 is a prime.

It is a super-2 number, since 2×100113000113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100113000094 and 100113000103.

It is not an unprimeable number, because it can be changed into a prime (100113000413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7150928573 + ... + 7150928586.

It is an arithmetic number, because the mean of its divisors is an integer number (28603714320).

Almost surely, 2^100113000113 is an apocalyptic number.

It is an amenable number.

100113000113 is a deficient number, since it is larger than the sum of its proper divisors (14301857167).

100113000113 is an equidigital number, since it uses as much as digits as its factorization.

100113000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14301857166.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 100113000113 its reverse (311000311001), we get a palindrome (411113311114).

The spelling of 100113000113 in words is "one hundred billion, one hundred thirteen million, one hundred thirteen", and thus it is an aban number.