Search a number
-
+
100113000131 = 412441780491
BaseRepresentation
bin101110100111100110…
…0110010011011000011
3100120102001021100021202
41131033030302123003
53120012412001011
6113554041011415
710142615313644
oct1351714623303
9316361240252
10100113000131
11395041a6841
121749b783b6b
139596055521
144bba0776cb
15290e10b23b
hex174f3326c3

100113000131 has 4 divisors (see below), whose sum is σ = 102554780664. Its totient is φ = 97671219600.

The previous prime is 100113000067. The next prime is 100113000137. The reversal of 100113000131 is 131000311001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100113000131 - 26 = 100113000067 is a prime.

It is a super-2 number, since 2×1001130001312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100113000137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1220890205 + ... + 1220890286.

It is an arithmetic number, because the mean of its divisors is an integer number (25638695166).

Almost surely, 2100113000131 is an apocalyptic number.

100113000131 is a deficient number, since it is larger than the sum of its proper divisors (2441780533).

100113000131 is an equidigital number, since it uses as much as digits as its factorization.

100113000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2441780532.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 100113000131 its reverse (131000311001), we get a palindrome (231113311132).

The spelling of 100113000131 in words is "one hundred billion, one hundred thirteen million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 41 2441780491 100113000131