10011311133 has 4 divisors (see below), whose sum is σ = 13348414848. Its totient is φ = 6674207420.

The previous prime is 10011311113. The next prime is 10011311137. The reversal of 10011311133 is 33111311001.

10011311133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10011311133 - 2⁶ = 10011311069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10011311137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668551853 + ... + 1668551858.

It is an arithmetic number, because the mean of its divisors is an integer number (3337103712).

Almost surely, 2^10011311133 is an apocalyptic number.

It is an amenable number.

10011311133 is a deficient number, since it is larger than the sum of its proper divisors (3337103715).

10011311133 is an equidigital number, since it uses as much as digits as its factorization.

10011311133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3337103714.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 10011311133 its reverse (33111311001), we get a palindrome (43122622134).

The spelling of 10011311133 in words is "ten billion, eleven million, three hundred eleven thousand, one hundred thirty-three".