100113113103221 has 4 divisors (see below), whose sum is σ = 105382224319200. Its totient is φ = 94844001887244.

The previous prime is 100113113103173. The next prime is 100113113103247. The reversal of 100113113103221 is 122301311311001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100113113103221 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 100113113103193 and 100113113103202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100113113103251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2634555607961 + ... + 2634555607998.

It is an arithmetic number, because the mean of its divisors is an integer number (26345556079800).

Almost surely, 2^{100113113103221} is an apocalyptic number.

It is an amenable number.

100113113103221 is a deficient number, since it is larger than the sum of its proper divisors (5269111215979).

100113113103221 is an equidigital number, since it uses as much as digits as its factorization.

100113113103221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5269111215978.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 100113113103221 its reverse (122301311311001), we get a palindrome (222414424414222).

The spelling of 100113113103221 in words is "one hundred trillion, one hundred thirteen billion, one hundred thirteen million, one hundred three thousand, two hundred twenty-one".