10011323013 has 4 divisors (see below), whose sum is σ = 13348430688. Its totient is φ = 6674215340.

The previous prime is 10011322949. The next prime is 10011323017. The reversal of 10011323013 is 31032311001.

10011323013 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31032311001 = 3 ⋅10344103667.

It is a cyclic number.

It is not a de Polignac number, because 10011323013 - 2⁶ = 10011322949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10011322983 and 10011323001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10011323017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668553833 + ... + 1668553838.

It is an arithmetic number, because the mean of its divisors is an integer number (3337107672).

Almost surely, 2^10011323013 is an apocalyptic number.

It is an amenable number.

10011323013 is a deficient number, since it is larger than the sum of its proper divisors (3337107675).

10011323013 is an equidigital number, since it uses as much as digits as its factorization.

10011323013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3337107674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10011323013 its reverse (31032311001), we get a palindrome (41043634014).

The spelling of 10011323013 in words is "ten billion, eleven million, three hundred twenty-three thousand, thirteen".