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10011333035 = 511199580223
BaseRepresentation
bin10010101001011100…
…01101000110101011
3221211201002102010102
421110232031012223
5131000400124120
64333225340015
7503042632604
oct112456150653
927751072112
1010011333035
114278155760
121b3493760b
13c37157a02
146ad872dab
153d8d9ad75
hex254b8d1ab

10011333035 has 16 divisors (see below), whose sum is σ = 13795522560. Its totient is φ = 6897759840.

The previous prime is 10011332983. The next prime is 10011333067. The reversal of 10011333035 is 53033311001.

10011333035 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10011333035 - 216 = 10011267499 is a prime.

It is a super-2 number, since 2×100113330352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10011332998 and 10011333016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4789067 + ... + 4791156.

It is an arithmetic number, because the mean of its divisors is an integer number (862220160).

Almost surely, 210011333035 is an apocalyptic number.

10011333035 is a deficient number, since it is larger than the sum of its proper divisors (3784189525).

10011333035 is a wasteful number, since it uses less digits than its factorization.

10011333035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9580258.

The product of its (nonzero) digits is 405, while the sum is 20.

Adding to 10011333035 its reverse (53033311001), we get a palindrome (63044644036).

The spelling of 10011333035 in words is "ten billion, eleven million, three hundred thirty-three thousand, thirty-five".

Divisors: 1 5 11 19 55 95 209 1045 9580223 47901115 105382453 182024237 526912265 910121185 2002266607 10011333035