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100116050115 = 3562171073573
BaseRepresentation
bin101110100111101100…
…0011011000011000011
3100120102021000022002010
41131033120123003003
53120014202100430
6113554230224003
710142653246014
oct1351730330303
9316367008063
10100116050115
113950599a294
12174a07b5003
139596882853
144bba62d00b
15290e50ecb0
hex174f61b0c3

100116050115 has 16 divisors (see below), whose sum is σ = 160211595168. Its totient is φ = 53386588416.

The previous prime is 100116050087. The next prime is 100116050129. The reversal of 100116050115 is 511050611001.

It is a happy number.

It is not a de Polignac number, because 100116050115 - 213 = 100116041923 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100116050091 and 100116050100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 443532 + ... + 630041.

It is an arithmetic number, because the mean of its divisors is an integer number (10013224698).

Almost surely, 2100116050115 is an apocalyptic number.

100116050115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

100116050115 is a deficient number, since it is larger than the sum of its proper divisors (60095545053).

100116050115 is a wasteful number, since it uses less digits than its factorization.

100116050115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1079798.

The product of its (nonzero) digits is 150, while the sum is 21.

Adding to 100116050115 its reverse (511050611001), we get a palindrome (611166661116).

The spelling of 100116050115 in words is "one hundred billion, one hundred sixteen million, fifty thousand, one hundred fifteen".

Divisors: 1 3 5 15 6217 18651 31085 93255 1073573 3220719 5367865 16103595 6674403341 20023210023 33372016705 100116050115