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100121013023 = 711410155113
BaseRepresentation
bin101110100111110101…
…1010110101100011111
3100120102121100102220112
41131033223112230133
53120021434404043
6113554524440235
710143043366103
oct1351753265437
9316377312815
10100121013023
1139508779a69
12174a23a907b
1395978cc795
144bbb161903
15290eb90518
hex174fad6b1f

100121013023 has 4 divisors (see below), whose sum is σ = 101531168208. Its totient is φ = 98710857840.

The previous prime is 100121012989. The next prime is 100121013043. The reversal of 100121013023 is 320310121001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100121013023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100121012989 and 100121013007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100121013043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 705077486 + ... + 705077627.

It is an arithmetic number, because the mean of its divisors is an integer number (25382792052).

Almost surely, 2100121013023 is an apocalyptic number.

100121013023 is a deficient number, since it is larger than the sum of its proper divisors (1410155185).

100121013023 is an equidigital number, since it uses as much as digits as its factorization.

100121013023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1410155184.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 100121013023 its reverse (320310121001), we get a palindrome (420431134024).

The spelling of 100121013023 in words is "one hundred billion, one hundred twenty-one million, thirteen thousand, twenty-three".

Divisors: 1 71 1410155113 100121013023