10012111112021 has 4 divisors (see below), whose sum is σ = 10018011002412. Its totient is φ = 10006211221632.

The previous prime is 10012111111997. The next prime is 10012111112023. The reversal of 10012111112021 is 12021111121001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9116087949796 + 896023162225 = 3019286^2 + 946585^2 .

It is a cyclic number.

It is not a de Polignac number, because 10012111112021 - 2²² = 10012106917717 is a prime.

It is a super-3 number, since 3×10012111112021³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10012111111987 and 10012111112005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10012111112023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2949942650 + ... + 2949946043.

It is an arithmetic number, because the mean of its divisors is an integer number (2504502750603).

Almost surely, 2^{10012111112021} is an apocalyptic number.

It is an amenable number.

10012111112021 is a deficient number, since it is larger than the sum of its proper divisors (5899890391).

10012111112021 is an equidigital number, since it uses as much as digits as its factorization.

10012111112021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5899890390.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 10012111112021 its reverse (12021111121001), we get a palindrome (22033222233022).

The spelling of 10012111112021 in words is "ten trillion, twelve billion, one hundred eleven million, one hundred twelve thousand, twenty-one".