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10012113133 = 111019011803
BaseRepresentation
bin10010101001100010…
…01011100011101101
3221211202120001012221
421110301023203231
5131001100110013
64333254155341
7503052362131
oct112461134355
927752501187
1010012113133
114278638870
121b35052b51
13c3736bac9
146ad9d73c1
153d8ea208d
hex254c4b8ed

10012113133 has 8 divisors (see below), whose sum is σ = 11030448096. Its totient is φ = 9011802000.

The previous prime is 10012113109. The next prime is 10012113143. The reversal of 10012113133 is 33131121001.

10012113133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10012113133 - 213 = 10012104941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10012113143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4504791 + ... + 4507012.

It is an arithmetic number, because the mean of its divisors is an integer number (1378806012).

Almost surely, 210012113133 is an apocalyptic number.

It is an amenable number.

10012113133 is a deficient number, since it is larger than the sum of its proper divisors (1018334963).

10012113133 is a wasteful number, since it uses less digits than its factorization.

10012113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9011915.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10012113133 its reverse (33131121001), we get a palindrome (43143234134).

The spelling of 10012113133 in words is "ten billion, twelve million, one hundred thirteen thousand, one hundred thirty-three".

Divisors: 1 11 101 1111 9011803 99129833 910192103 10012113133