Base | Representation |
---|---|
bin | 1001000110110010000001… |
… | …1101110001111001011011 |
3 | 1022110011000101210222200212 |
4 | 2101230200131301321123 |
5 | 2303014302020210233 |
6 | 33143300150121335 |
7 | 2052231335046665 |
oct | 221544035617133 |
9 | 38404011728625 |
10 | 10012113444443 |
11 | 321012802a130 |
12 | 11584b865024b |
13 | 5781a4960126 |
14 | 268835c3b535 |
15 | 125688621a48 |
hex | 91b20771e5b |
10012113444443 has 4 divisors (see below), whose sum is σ = 10922305575768. Its totient is φ = 9101921313120.
The previous prime is 10012113444433. The next prime is 10012113444461. The reversal of 10012113444443 is 34444431121001.
10012113444443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10012113444443 - 210 = 10012113443419 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10012113444413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455096065646 + ... + 455096065667.
It is an arithmetic number, because the mean of its divisors is an integer number (2730576393942).
Almost surely, 210012113444443 is an apocalyptic number.
10012113444443 is a deficient number, since it is larger than the sum of its proper divisors (910192131325).
10012113444443 is an equidigital number, since it uses as much as digits as its factorization.
10012113444443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 910192131324.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 10012113444443 its reverse (34444431121001), we get a palindrome (44456544565444).
The spelling of 10012113444443 in words is "ten trillion, twelve billion, one hundred thirteen million, four hundred forty-four thousand, four hundred forty-three".
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