100121201000111 has 4 divisors (see below), whose sum is σ = 104474296695792. Its totient is φ = 95768105304432.

The previous prime is 100121201000101. The next prime is 100121201000131. The reversal of 100121201000111 is 111000102121001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100121201000111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100121201000092 and 100121201000101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100121201000101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2176547847806 + ... + 2176547847851.

It is an arithmetic number, because the mean of its divisors is an integer number (26118574173948).

Almost surely, 2^{100121201000111} is an apocalyptic number.

100121201000111 is a deficient number, since it is larger than the sum of its proper divisors (4353095695681).

100121201000111 is an equidigital number, since it uses as much as digits as its factorization.

100121201000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4353095695680.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 100121201000111 its reverse (111000102121001), we get a palindrome (211121303121112).

The spelling of 100121201000111 in words is "one hundred trillion, one hundred twenty-one billion, two hundred one million, one hundred eleven", and thus it is an aban number.