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10012124103151 = 28773134796821
BaseRepresentation
bin1001000110110010000100…
…0110011100000111101111
31022110011001010212111200211
42101230201012130013233
52303014312232300101
633143301210403251
72052231524461642
oct221544106340757
938404033774624
1010012124103151
11321013304a185
121158500130527
135781a6c22761
14268837413a59
15125689529c51
hex91b2119c1ef

10012124103151 has 4 divisors (see below), whose sum is σ = 10012159187704. Its totient is φ = 10012089018600.

The previous prime is 10012124103143. The next prime is 10012124103161. The reversal of 10012124103151 is 15130142121001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10012124103151 - 23 = 10012124103143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10012124103161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17110680 + ... + 17686141.

It is an arithmetic number, because the mean of its divisors is an integer number (2503039796926).

Almost surely, 210012124103151 is an apocalyptic number.

10012124103151 is a deficient number, since it is larger than the sum of its proper divisors (35084553).

10012124103151 is an equidigital number, since it uses as much as digits as its factorization.

10012124103151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35084552.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 10012124103151 its reverse (15130142121001), we get a palindrome (25142266224152).

The spelling of 10012124103151 in words is "ten trillion, twelve billion, one hundred twenty-four million, one hundred three thousand, one hundred fifty-one".

Divisors: 1 287731 34796821 10012124103151