100121332021 has 4 divisors (see below), whose sum is σ = 100125412992. Its totient is φ = 100117251052.

The previous prime is 100121331983. The next prime is 100121332049. The reversal of 100121332021 is 120233121001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100121332021 - 2¹⁵ = 100121299253 is a prime.

It is a super-3 number, since 3×100121332021³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100121331986 and 100121332004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100121332321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003461 + ... + 2052826.

It is an arithmetic number, because the mean of its divisors is an integer number (25031353248).

Almost surely, 2^100121332021 is an apocalyptic number.

It is an amenable number.

100121332021 is a deficient number, since it is larger than the sum of its proper divisors (4080971).

100121332021 is an equidigital number, since it uses as much as digits as its factorization.

100121332021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4080970.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 100121332021 its reverse (120233121001), we get a palindrome (220354453022).

The spelling of 100121332021 in words is "one hundred billion, one hundred twenty-one million, three hundred thirty-two thousand, twenty-one".