10012143233131 has 4 divisors (see below), whose sum is σ = 10782308097232. Its totient is φ = 9241978369032.

The previous prime is 10012143233077. The next prime is 10012143233153. The reversal of 10012143233131 is 13133234121001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10012143233131 is a prime.

It is a super-2 number, since 2×10012143233131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10012143233096 and 10012143233105.

It is not an unprimeable number, because it can be changed into a prime (10012143033131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385082432031 + ... + 385082432056.

It is an arithmetic number, because the mean of its divisors is an integer number (2695577024308).

Almost surely, 2^{10012143233131} is an apocalyptic number.

10012143233131 is a deficient number, since it is larger than the sum of its proper divisors (770164864101).

10012143233131 is an equidigital number, since it uses as much as digits as its factorization.

10012143233131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 770164864100.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 10012143233131 its reverse (13133234121001), we get a palindrome (23145377354132).

The spelling of 10012143233131 in words is "ten trillion, twelve billion, one hundred forty-three million, two hundred thirty-three thousand, one hundred thirty-one".