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10012200110303 = 79126736710257
BaseRepresentation
bin1001000110110010010110…
…1000011000100011011111
31022110011020102220001220112
42101230211220120203133
52303014441212012203
633143312523440235
72052233436515066
oct221544550304337
938404212801815
1010012200110303
113210171a43506
12115852168607b
135781b98b55c1
1426884355b1dd
151256910406d8
hex91b25a188df

10012200110303 has 4 divisors (see below), whose sum is σ = 10138936820640. Its totient is φ = 9885463399968.

The previous prime is 10012200110299. The next prime is 10012200110309. The reversal of 10012200110303 is 30301100221001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10012200110303 - 22 = 10012200110299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10012200110309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63368355050 + ... + 63368355207.

It is an arithmetic number, because the mean of its divisors is an integer number (2534734205160).

Almost surely, 210012200110303 is an apocalyptic number.

10012200110303 is a deficient number, since it is larger than the sum of its proper divisors (126736710337).

10012200110303 is an equidigital number, since it uses as much as digits as its factorization.

10012200110303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 126736710336.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 10012200110303 its reverse (30301100221001), we get a palindrome (40313300331304).

The spelling of 10012200110303 in words is "ten trillion, twelve billion, two hundred million, one hundred ten thousand, three hundred three".

Divisors: 1 79 126736710257 10012200110303