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100122031143 = 3265111170857
BaseRepresentation
bin101110100111110111…
…1001111010000100111
3100120102200021011111200
41131033233033100213
53120022214444033
6113555002333543
710143055136301
oct1351757172047
9316380234450
10100122031143
1139509304992
12174a27ba2b3
139597b98014
144bbb348971
15290ece2013
hex174fbcf427

100122031143 has 12 divisors (see below), whose sum is σ = 144623779248. Its totient is φ = 66746604960.

The previous prime is 100122031123. The next prime is 100122031187. The reversal of 100122031143 is 341130221001.

It is not a de Polignac number, because 100122031143 - 210 = 100122030119 is a prime.

It is a super-2 number, since 2×1001220311432 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100122031103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 500571 + ... + 671427.

It is an arithmetic number, because the mean of its divisors is an integer number (12051981604).

Almost surely, 2100122031143 is an apocalyptic number.

100122031143 is a deficient number, since it is larger than the sum of its proper divisors (44501748105).

100122031143 is a wasteful number, since it uses less digits than its factorization.

100122031143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 235974 (or 235971 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 100122031143 its reverse (341130221001), we get a palindrome (441252252144).

The spelling of 100122031143 in words is "one hundred billion, one hundred twenty-two million, thirty-one thousand, one hundred forty-three".

Divisors: 1 3 9 65111 170857 195333 512571 585999 1537713 11124670127 33374010381 100122031143