10012230434113 has 4 divisors (see below), whose sum is σ = 10013758792128. Its totient is φ = 10010702076100.

The previous prime is 10012230434081. The next prime is 10012230434131. The reversal of 10012230434113 is 31143403221001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10012230434113 - 2⁵ = 10012230434081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10012230464113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 764169181 + ... + 764182282.

It is an arithmetic number, because the mean of its divisors is an integer number (2503439698032).

Almost surely, 2^{10012230434113} is an apocalyptic number.

It is an amenable number.

10012230434113 is a deficient number, since it is larger than the sum of its proper divisors (1528358015).

10012230434113 is an equidigital number, since it uses as much as digits as its factorization.

10012230434113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1528358014.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 10012230434113 its reverse (31143403221001), we get a palindrome (41155633655114).

The spelling of 10012230434113 in words is "ten trillion, twelve billion, two hundred thirty million, four hundred thirty-four thousand, one hundred thirteen".