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10012231311300 = 22335219962920269
BaseRepresentation
bin1001000110110010011101…
…1111011001111111000100
31022110011022121121020122000
42101230213133121333010
52303020022203430200
633143320000305300
72052234265645101
oct221544737317704
938404277536560
1010012231311300
113210188614259
121158530012230
135781c31bb12a
1426884775daa8
15125693b55300
hex91b277d9fc4

10012231311300 has 288 divisors, whose sum is σ = 33886737360000. Its totient is φ = 2529018339840.

The previous prime is 10012231311283. The next prime is 10012231311337. The reversal of 10012231311300 is 311313221001.

10012231311300 is a `hidden beast` number, since 1 + 0 + 0 + 1 + 22 + 31 + 311 + 300 = 666.

It is a super-2 number, since 2×100122313113002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 493957566 + ... + 493977834.

It is an arithmetic number, because the mean of its divisors is an integer number (117662282500).

Almost surely, 210012231311300 is an apocalyptic number.

10012231311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10012231311300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16943368680000).

10012231311300 is an abundant number, since it is smaller than the sum of its proper divisors (23874506048700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10012231311300 is a wasteful number, since it uses less digits than its factorization.

10012231311300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29940 (or 29927 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 10012231311300 its reverse (311313221001), we get a palindrome (10323544532301).

The spelling of 10012231311300 in words is "ten trillion, twelve billion, two hundred thirty-one million, three hundred eleven thousand, three hundred".