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100123314303 = 333374438101
BaseRepresentation
bin101110100111111010…
…0001000100001111111
3100120102202200100200010
41131033310020201333
53120023032024203
6113555050034303
710143102062265
oct1351764104177
9316382610603
10100123314303
113950a000a51
12174a3118993
13959822709c
144bbb5a0435
15290ee97303
hex174fd0887f

100123314303 has 4 divisors (see below), whose sum is σ = 133497752408. Its totient is φ = 66748876200.

The previous prime is 100123314283. The next prime is 100123314311. The reversal of 100123314303 is 303413321001.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 100123314303 - 226 = 100056205439 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100123314303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100123314373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16687219048 + ... + 16687219053.

It is an arithmetic number, because the mean of its divisors is an integer number (33374438102).

Almost surely, 2100123314303 is an apocalyptic number.

100123314303 is a deficient number, since it is larger than the sum of its proper divisors (33374438105).

100123314303 is an equidigital number, since it uses as much as digits as its factorization.

100123314303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33374438104.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 100123314303 its reverse (303413321001), we get a palindrome (403536635304).

The spelling of 100123314303 in words is "one hundred billion, one hundred twenty-three million, three hundred fourteen thousand, three hundred three".

Divisors: 1 3 33374438101 100123314303