1001240433111 has 4 divisors (see below), whose sum is σ = 1334987244152. Its totient is φ = 667493622072.

The previous prime is 1001240433103. The next prime is 1001240433169. The reversal of 1001240433111 is 1113340421001.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1001240433111 - 2³ = 1001240433103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1001240433511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166873405516 + ... + 166873405521.

It is an arithmetic number, because the mean of its divisors is an integer number (333746811038).

Almost surely, 2^{1001240433111} is an apocalyptic number.

1001240433111 is a deficient number, since it is larger than the sum of its proper divisors (333746811041).

1001240433111 is an equidigital number, since it uses as much as digits as its factorization.

1001240433111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333746811040.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1001240433111 its reverse (1113340421001), we get a palindrome (2114580854112).

The spelling of 1001240433111 in words is "one trillion, one billion, two hundred forty million, four hundred thirty-three thousand, one hundred eleven".