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10012414431 = 33337471477
BaseRepresentation
bin10010101001100100…
…10101000111011111
3221211210010100112010
421110302111013133
5131001134230211
64333304442303
7503055055425
oct112462250737
927753110463
1010012414431
114278824178
121b35179393
13c37445ca6
146ada75115
153d90114a6
hex254c951df

10012414431 has 4 divisors (see below), whose sum is σ = 13349885912. Its totient is φ = 6674942952.

The previous prime is 10012414409. The next prime is 10012414463. The reversal of 10012414431 is 13441421001.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10012414431 - 211 = 10012412383 is a prime.

It is a super-2 number, since 2×100124144312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10012414398 and 10012414407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10012414481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668735736 + ... + 1668735741.

It is an arithmetic number, because the mean of its divisors is an integer number (3337471478).

Almost surely, 210012414431 is an apocalyptic number.

10012414431 is a deficient number, since it is larger than the sum of its proper divisors (3337471481).

10012414431 is an equidigital number, since it uses as much as digits as its factorization.

10012414431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3337471480.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 10012414431 its reverse (13441421001), we get a palindrome (23453835432).

The spelling of 10012414431 in words is "ten billion, twelve million, four hundred fourteen thousand, four hundred thirty-one".

Divisors: 1 3 3337471477 10012414431