10012432433 has 4 divisors (see below), whose sum is σ = 10013184000. Its totient is φ = 10011680868.

The previous prime is 10012432411. The next prime is 10012432447. The reversal of 10012432433 is 33423421001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33423421001 = 31 ⋅1078174871.

It is a cyclic number.

It is not a de Polignac number, because 10012432433 - 2⁶ = 10012432369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10012432399 and 10012432408.

It is not an unprimeable number, because it can be changed into a prime (10012432403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355433 + ... + 382566.

It is an arithmetic number, because the mean of its divisors is an integer number (2503296000).

Almost surely, 2^10012432433 is an apocalyptic number.

It is an amenable number.

10012432433 is a deficient number, since it is larger than the sum of its proper divisors (751567).

10012432433 is an equidigital number, since it uses as much as digits as its factorization.

10012432433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 751566.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 10012432433 its reverse (33423421001), we get a palindrome (43435853434).

The spelling of 10012432433 in words is "ten billion, twelve million, four hundred thirty-two thousand, four hundred thirty-three".