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10012432447 is a prime number
BaseRepresentation
bin10010101001100100…
…11001100000111111
3221211210011021020101
421110302121200333
5131001140314242
64333305101531
7503055162103
oct112462314077
927753137211
1010012432447
114278836766
121b351878a7
13c37451254
146ada7b903
153d90169b7
hex254c9983f

10012432447 has 2 divisors, whose sum is σ = 10012432448. Its totient is φ = 10012432446.

The previous prime is 10012432411. The next prime is 10012432453. The reversal of 10012432447 is 74423421001.

10012432447 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (74423421001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10012432447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012432487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006216223 + 5006216224.

It is an arithmetic number, because the mean of its divisors is an integer number (5006216224).

Almost surely, 210012432447 is an apocalyptic number.

10012432447 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012432447 is an equidigital number, since it uses as much as digits as its factorization.

10012432447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 28.

Adding to 10012432447 its reverse (74423421001), we get a palindrome (84435853448).

The spelling of 10012432447 in words is "ten billion, twelve million, four hundred thirty-two thousand, four hundred forty-seven".