Base | Representation |
---|---|
bin | 101110100111111101… |
… | …1110111000111110111 |
3 | 100120102220111021121112 |
4 | 1131033323313013313 |
5 | 3120024041341101 |
6 | 113555201305235 |
7 | 10143125230454 |
oct | 1351773670767 |
9 | 316386437545 |
10 | 100125340151 |
11 | 39510165001 |
12 | 174a393521b |
13 | 9598786205 |
14 | 4bbb96a82b |
15 | 29102476bb |
hex | 174fef71f7 |
100125340151 has 4 divisors (see below), whose sum is σ = 101392749600. Its totient is φ = 98857930704.
The previous prime is 100125340129. The next prime is 100125340153. The reversal of 100125340151 is 151043521001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100125340151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100125340153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 633704606 + ... + 633704763.
It is an arithmetic number, because the mean of its divisors is an integer number (25348187400).
Almost surely, 2100125340151 is an apocalyptic number.
100125340151 is a deficient number, since it is larger than the sum of its proper divisors (1267409449).
100125340151 is an equidigital number, since it uses as much as digits as its factorization.
100125340151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1267409448.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 100125340151 its reverse (151043521001), we get a palindrome (251168861152).
The spelling of 100125340151 in words is "one hundred billion, one hundred twenty-five million, three hundred forty thousand, one hundred fifty-one".
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